Hackerrank occupations pivot solution Hacker 84072 submitted solutions for challenges 49593 and 63132, so the total score = 100 + 0 = 100. Sample queried records: R 19. I think this is a much simpler MySQL solution: CREATE VIEW OccupationsView AS SELECT ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS row_num, Occupation, Name FROM OCCUPATIONS; Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Create a HackerRank account Be part of a 23 million-strong community of developers. Blog; Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. /*Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Try1: Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Enterprises Small and medium teams Startups hackerrank-advanced-select. com/challenges/japanese-cities-nameLe Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Contribute to sknsht/HackerRank development by creating an account on GitHub. Occupation AND a. ; Here, MIN function in the outer SELECT query is used to select Name from the group of 1 Name & 3 NULL. 📅 Last Modified: Mon, 27 Aug 2018 21:27:49 GMT. Occupations contain four occupation types: Doctor, Professor, Singer and Actor. I translated your solution to something that works in MS SQL. com/challenges/occupations/p [Solved] Occupations in SQL solution in Hackerrank Try With Live Editor . 8 months ago + 0 comments. Blame. HackerRank SQL Interview Question: Level Medium. HackerRank practice exercise for Pivoting in MySQL - nborbas/SQL_Pivoting_Practice_HackerRank Check my solution under solution. me/AnalyticsKidaIf you want to try this question then-Question - https://www. Solution: Creating ruleset — it’s known that there is only one ROOT and it is a value for P = Null HackerRank SQL: Occupations. HackerRank's code block convert "@r1" into "(/r1)", so all This approach is easy to use and understandable. You signed out in another tab or window. The output column headers should be Doctor, Professor In the solution below we need a subquery to extract the data where we informed the fields the will became our data and columns, and after a row number, this last its necessary because the pivot functions need an aggregation function, how we are working with strings the only function that work is MAX, however this function bring only the max Data at Occupations Table. Learned many things from this problem MySql Solution. Contribute to rene-d/hackerrank development by creating an account on GitHub. We use cookies to ensure you have the My Solution using Oracle SELECT Doctor , Professor , Singer , Actor FROM ( SELECT ROW_NUMBER () OVER ( PARTITION BY Occupation ORDER BY Name ) rn , Name , Occupation FROM Occupations ) PIVOT ( MAX ( Name ) FOR occupation IN ( ' Doctor ' Doctor , ' Professor ' Professor , ' Singer ' Singer Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The goal is to transform the data, from one data format into a different str Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Note: Print NULL when there are no more names corresponding to an Hackerrank occupations problem link. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. Raw. The output column Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. So now the fun part. This repository contains solutions to all the HackerRank SQL Practice Questions - HackerRank-SQL-Challenges-Solutions/Advanced Select/Occupations. For this reason, column aliases defined in the SELECT are available to the ORDER BY. Input Format. Problem Link: https://www. NAME, SingTable. My Solution: with doctor as (Select name, ROW_NUMBER() OVER(orde Occupations. Input Format The OCCUPATIONS Solutions for all SQL challenges on HackerRank executed on MySQL and MS SQL Server. The output column headers should be It might help to think of it in terms of writing it without PIVOT. NAME FROM (SELECT OCCUPATION, [NAME], ROW_NUMBER() OVER(PARTITION BY OCCUPATION ORDER BY [NAME] ASC) AS ID FROM OCCUPATIONS WHERE OCCUPATION = 'Doctor') As DocTable FULL OUTER JOIN /*Solution with Oracle Sql*/ WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' THEN Name END) Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. occupation, ROW_NUMBER() OVER ( PARTITION BY Occupation ORDER BY Name) as row from occupations) occup pivot (min(name) for occupation in ([Doctor], [Professor] ,[Singer],[Actor])) as pivottable; 0 | Permalink. Copy path. https://www. Here is my work; Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be Doctor You signed in with another tab or window. chaulkar_shreyas. com/dev. The OCCUPATIONS Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Code. Problem Solving (Basic) Get Certified. The output column See https://docs. In my solution I have solved it but my solution is not flexible but It is very easy to understand let me explain you here in the question I have constructed 4 new tables each tables consisting of names of specific Code your solution in our custom editor or code in your own environment and upload your solution as a file. be/7C8wlTNUQzAinput an integer Contains solutions for all Hackerrank Sql problems - Hackerrank-Sql-solutions/Advanced Select -- Occupations at main · vmlrj02/Hackerrank-Sql-solutions. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. MS SQL SERVER SOLUTION : SELECT MAX (CASE WHEN OCCUPATION = "DOCTOR" THEN NAME END), MAX Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Preview. , OCCUPATIONS. In this post, we will be covering all the solutions to SQL on the HackerRank platform. The output column headers Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. MySQL is quite Problem. Note: Print NULL when there are no more names You signed in with another tab or window. instagram. Note: Print NULLwhen there are no more names corresponding See more Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Solutions By company size. com/challenges/occupations/problem?isFullScreen=trueProblem Name: OccupationsDifficulty Level: MediumKey topics here:- Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. #hackerranksql#sqlgoldbadgeHey guys,Welcome to my channel In this video I have explained Sql challenge "OCCUPATIONS" step by step . Beyond that, variables are an extension to SQL. It is very important that you all first give it a try & brainstorm yourselves before having a look at the solutions. HackerRank SQL: Occupations Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Feb 15, 2024 Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Table: 'OCCUPATIONS' Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Medium Max Score: 30 Success Rate: 91. Occupations explanation - mtthwmths/hackerrank-solutions GitHub Wiki Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Please read our cookie policy for please help me solve this problem: You are given a table, containing two columns: column is one of the followings: Doctor Professor Singer Actor Write a query to output the names underneath the I used a similar query, but my order for the professors is incorrect. Contribute to pbhakuni/HackerRank development by creating an account on GitHub. AS R, NAME, OCCUPATION FROM OCCUPATIONS. Return to all comments →. Sample Output. select doctor, professor, singer, actor . See the problem statement, sample input and output, and the query code with In this HackerRank Functions in SQL problem solution, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). Stand out from the crowd. The output column headers should be Doctor, Professor, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be Doctor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. -- This is my solution for MS SQL without 'pivot' with doctor as ( select name as doctor , row_number () over ( order by name ) as rn from occupations where occupation = ' Doctor ' ), actor as ( select name as actor , row_number () over ( order by name ) as rn from occupations where occupation = ' Actor ' ), singer as ( select name as singer In this part of the query, we use conditional aggregation to pivot the data. Reload to refresh your session. Submissions. Problem. I am looking for solution using pivot and without using Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Anyway, I think solution is to pivot the data. We create columns for each occupation (Doctor, Professor, Singer, Actor), and for each row number (rn), we pick the name that belongs to the respective occupation and place it in the corresponding column. Occupations in SQL solution in Hackerrank Intermediate Ex: #238 [Solved] Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The STATION table is described as Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. ; ORDER BY NAME is used to get all the names first and then NULL. 311 lines (259 loc) · 8. The output column headers should be Doctor , Professor , Singer Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. We use cookies to ensure you have the best browsing experience on our website. So in advance; I'm sorry if this is too basic stuff or my query is too messy. The output should consist of four columns (Doctor, Professor, Singer, and Actor) in that HackerRank-AdvancedSelect-Occupations - pivot, row_number 1 minute read Occupations - pivot, row_number. I wrote a query but it didn't work. com/challenges/occupationsLearn: Buil Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Source: HackerRank. HackerRank SQL: Occupations. select Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. For the task I’ve decided to use “case” statement and tinker a little with joins. *Check with my_solution : SELECT Doctor, Professor, Singer, Actor FROM ( SELECT OCCUPATION, NAME, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) RankTable FROM OCCUPATIONS ) RT PIVOT ( MIN Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. NAME, ActTable. You switched accounts on another tab or window. I share my solution in Oracle: select DC, PR, SN, AC from ( select occupation , name , row_number() over (partition by occupation order by name) as ra from occupations ) pivot (max(name) for occupation in ('Doctor' as Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Previous Video Links: program to read two numbers from the keyboard and display the larger value on the screen: https://youtu. Name) AS rank FROM Occupations AS a Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. hackerrank. com/blog/sql-over Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. MySQL pivot solution. ; SET keyword is used to initiate variables like d, p, s & a with 0 value. You signed in with another tab or window. HackerRank SQL Problems and Solutions — 1 Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. : enclosed in parentheses). Full Hacker 74842 submitted solutions for challenges 19797 and 63132, so the total score = max(98, 5) + 76 = 174. you can use MAX instead of MIN here. Pivot the Occupation column in OCCUPATIONS so that each Name First, where does it say that in the order of operations that a SELECT is executed before the ORDER BY?That statement is simply not true. 9 years ago + 16 comments. 53 KB. Inside you will find the solutions to all HackerRank SQL Questions. e. with Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. --My MS SQL Solution;WITH base_cte as ( select * ,ROW_NUMBER over (partition by occupation order by name) as [RowID] from Occupations ) SELECT [Doctor],[Professor],[Singer],[Actor] FROM (select RowID ,name,Occupation Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The OCCUPATIONS Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Occupation = b. Query the number of ocurrences of each Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please follow us https://www. 5 of 6; Submit to see results When you're ready, submit your solution! Remember, you can go back and refine your code anytime. The output column headers should be /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. . Solve Challenge. microsoft. You basicly create an CTE that includes the OCCUPATIONS table plus an added ID column, this is needed for sorting the results correctly, this is the CTE I called KEYED_OCCUPATIONS. These recursive functions you constructed {@r1:=@r1+1} is basically the same as creating a rank column partitioned by Occupation:with cte as ( select RANK() OVER (PARTITION BY Occupation ORDER BY Name) as Rank, case when Occupation='Doctor' then Name else null end as Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. MySQL solution. 65%. occupation as profession, OCCUPATIONS. HackerRank is a platform for competitive coding. Occupation, a. The output column headers should be Doctor, Professor, Singer, and Actor, respectively Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. 09%. 19. Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. sql at main · Pavith19/HackerRank-SQL-Challenges-Solutions /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Problem. Pivot the occupation column in occupations so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Telegram learner's community - https://t. Discussions. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The total scores for hackers 4806, 26071, 80305, and 49438 can be similarly calculated. community/OVER ([PARTITION BY columns] [ORDER BY columns])https://learnsql. Here is my solution : (SELECT name, occupation, RANK OVER (PARTITION BY occupation ORDER BY name) AS ranke FROM occupations) PIVOT (MAX (name) FOR occupation IN (' Doctor ' as doc, ' Professor ' as pro, ' Singer Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SELECT a. Name > b. The output column headers should be Learn how to pivot the Occupation column in OCCUPATIONS table using SET, CASE WHEN, ROW_NUM, ORDER BY and GROUP BY in MySQL. Pivot the Occupation column in OCCUPATIONS so that each Name is Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. if you choose to interact with chat-gpt to find a good solution that's great, but I think chat-gpt will refers you dynamic queries or some ways like my query because there is no pivot operator like Microsoft SQL Server Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Jenny Ashley You signed in with another tab or window. The output column headers should be Doctor, Professor, Singer, and Actor, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Certification. For example, SELECT [Doctor] = MAX(CASE WHEN Occupation = 'Doctor' THEN Name END), [Professor] = MAX(CASE WHEN Occupation = 'Professor' THEN Name END), [Singer] = MAX(CASE WHEN Occupation = 'Singer' THEN Name END), [Actor] = MAX(CASE WHEN Occupation = 'Actor' Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Python (Basic) Get Certified. Top. Select min (if HackerRank is a technology hiring platform that is the standard for assessing developer skills for over 2,000+ companies around the world. Category - Hacker Rank Online Judge Maniruzzaman Akash 1 year ago 2027 0 Ex: #1 [Solved] Day 0: Hello, World solution in Hackerrank - Hacerrank solution C My solutions to HackerRank problems. Occupations. Solution Code snippet of hacker-rank challenge solution. In this Video Im solving the OCCUPATIONS Problem from Hackerrank SQL Problems. The output column headers should be Doctor, Professor, Singer, and Actor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Select MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS Actor FROM ( Select *, ROW_NUMBER() OVER Solution. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted ==== Steps 1 ==== select name, Doctor, Professor, Singer, Actor from occupations pivot (count (occupation) for occupation in (Doctor, Professor, Singer, Actor)) as p Out put: Aamina 1 0 0 0 Ashley 0 1 0 0 Belvet 0 1 0 0 Britney 0 1 0 0 Christeen 0 0 1 0 Eve 0 0 0 1 Jane 0 0 1 0 Jennifer 0 0 0 1 Jenny 0 0 1 0 Julia 1 0 0 0 Ketty 0 0 0 1 Kristeen A lesson that teaches you how to solve the following problem from the SQL section in HackerRank. Please read our cookie policy for / hackerRank_sql_solutions / 02_advanced_select / 03_occupations. YujiShen. We will go by our usual step by step Approach - Step 1: We will write the inner Query to fetch the required data Step 2 : We will pivot the data we Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. sql file! Exercise. sql at main · qanhnn12/SQL-Hackerrank-Challenge-Solutions Problem Statement: Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Binary Tree Nodes. 6 of 6 Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SIMPLE SQLSERVER SOLUTION . Simple solution without using Pivot/Window function in MS SQL Server: SELECT col FROM ( SELECT Name+'('+LEFT(Occupation,1)+')' as col, 1 as order_by FROM OCCUPATIONS MY SQL Solution. name as name from Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Explore Skills. The output column headers should Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Note: Print NULL when there are no more names corresponding to an occupation. com/en-us/sql/t-sql/functions/row-number-transact-sql?view=sql-server-2017 ROW_NUMBER () OVER (PARTITION BY Occupation ORDER BY Name) row_num, [Name], [Occupation] FROM Occupations ) AS /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. I'm new to SQL and struggled to find the solution for about 2 days in my spare time. Problem Statement: Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. WITH RankedOccupations AS ( -- Assign a row number to each name based on their occupation and sort them alphabetically SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) -- Pivot the table by occupations SELECT Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Really good stuff. from (select name, occupation, rownumber() over (partition by occupation order by name asc) rn from occupations) Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Saved searches Use saved searches to filter your results more quickly Oracle. SELECT [DOCTOR], [PROFESSOR], [SINGER], [ACTOR] FROM (SELECT ROW_NUMBER() OVER (PARTITION BY [OCCUPATION] ORDER BY NAME) AS RN, NAME, OCCUPATION FROM Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Occupations HackerRank Solution Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Jul 31, 2023 You signed in with another tab or window. Question¶ Solution¶ MySQL / MS SQL Server. - SQL-Hackerrank-Challenge-Solutions/Advanced Select/Occupations. Step 3: Select the columns and order the results Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please read our cookie policy for Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. md. Please read our cookie policy for SQL Hackerrank Occupations Query Solutions in MS SQLServer. Here is my solution using PIVOT function: SELECT Doctor, Professor, Singer, Actor FROM (SELECT *, ROW_NUMBER () I guess the row number function provides each distinct occupation with separate row numbers, like 1,2,3 for doctor and again 1,2,3 for professor since it was partitioning by occupation. If you guys have any doubt HackerRank personal solutions. Name, (SELECT COUNT(*) FROM Occupations AS b WHERE a. Output¶ 2) Occupations. The output column headers should be HackerRank offers a variety of skills, tracks and tutorials for you to learn and improve. SELECT DocTable. I'm new to sql and this community. Eg. To understand the above solution, Try to print the inner SELECT query first. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. HackerRank SQL Problems and Solutions — 1 A lesson that teaches you how to solve the following problem from the SQL section in HackerRank. Weather Observation Station 4 | Easy | HackerRank Find the difference between the total number of CITY entries in the table and the number of distinct CITY entries in the table. 4 of 6; Test your code You can compile your code and test it for errors and accuracy before submitting. You are viewing a single comment's thread. NAME, ProfTable. Take the HackerRank Certification Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. given in this site, we can think of product_name like an index for North, Central, South, West. Please read our cookie policy for My SQL Server solution, using PIVOT and CTE :- WITH numbered_names ( Name , Occupation , RN ) AS ( SELECT Name , Occupation , ROW_NUMBER () OVER ( PARTITION BY Occupation ORDER BY Name ) AS RN FROM Occupations ) SELECT Doctor , Professor , Singer , Actor FROM numbered_names PIVOT ( MAX ( Name ) Below are my solutions to all Medium SQL challenges on HackerRank. What is true is that the SELECT is evaluated by the compiler before the ORDER BY. For those who are struggling for a simple solution. Medium SQL (Intermediate) Max Score: 30 Success Rate: 97. 1) The PADS. File metadata and controls. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. This was curated after solving all 58 questions, and achieving a score of 1130 points (WR1) Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. To create a similar solution for our problem, we need SerialNo as an index for Doctor,Professor,Singer,Actor. oiij wxluzc iwfgow daa krmdpb lnwrm typatxn zncvo zofebn sjmr